169.Majority Element:修订间差异
创建页面,内容为“=Description= {{LeetCode |id=majority-elemen |no=169 |difficulty=Easy |category=Array |collection=Top 150 |title=Majority Element |summary=Given an array nums of size n, return the majority element..}} The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. Example 1: <syntaxhighlight lang="bash"> Input: nums = [3,2,3] Output: 3 </syntaxhighlight> Example 2: <syntaxhi…” |
无编辑摘要 |
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第23行: | 第23行: | ||
Output: 2 | Output: 2 | ||
</syntaxhighlight> | </syntaxhighlight> | ||
===HashMap=== | |||
{{Submission|runtime=12ms|memory=49.68MB|rp=33.25|mp=68.75}} | |||
<syntaxhighlight lang="bash"> | |||
class Solution { | |||
public int majorityElement(int[] nums) { | |||
Map<Integer, Integer> counts = new HashMap<>(); | |||
float half = nums.length / 2.0f; | |||
for(int i = 0; i < nums.length; i++) { | |||
int count = counts.getOrDefault(nums[i], 0) + 1; | |||
if(count > half) return nums[i]; | |||
counts.put(nums[i], count); | |||
} | |||
throw new RuntimeException("No majority element found"); | |||
} | |||
} | |||
</syntaxhighlight> | |||
[[Category:Algorithm]] | |||
[[Category:Array]] | |||
[[Category:LeetCode]] |
2024年2月19日 (一) 14:03的版本
Description
#169 | Majority Element | Easy | ||
---|---|---|---|---|
Array | Top 150 | |||
Given an array nums of size n, return the majority element.. |
The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array.
Example 1:
Input: nums = [3,2,3]
Output: 3
Example 2:
Input: nums = [2,2,1,1,1,2,2]
Output: 2
HashMap
Runtime 12ms |
|
Memory 49.68MB |
|
class Solution {
public int majorityElement(int[] nums) {
Map<Integer, Integer> counts = new HashMap<>();
float half = nums.length / 2.0f;
for(int i = 0; i < nums.length; i++) {
int count = counts.getOrDefault(nums[i], 0) + 1;
if(count > half) return nums[i];
counts.put(nums[i], count);
}
throw new RuntimeException("No majority element found");
}
}